Answer
$2x + \frac{{{3^x}}}{{\ln 3}} + C$
Work Step by Step
$$\eqalign{
& \int {\left( {2 + {3^x}} \right)} dx \cr
& {\text{Use the sum rule for integration}} \cr
& = \int 2 dx + \int {{3^x}} dx \cr
& {\text{From the table of indefinite integrals }} \cr
& \int c dx = cx + C{\text{ and }}\int {{b^x}} dx = \frac{{{b^x}}}{{\ln b}} + C \cr
& {\text{Then}}{\text{,}} \cr
& \int 2 dx + \int {{3^x}} dx = 2x + \frac{{{3^x}}}{{\ln 3}} + C \cr} $$