Answer
${e^x} + \ln \left| x \right| + C$
Work Step by Step
$$\eqalign{
& \int {\left( {{e^x} + \frac{1}{x}} \right)} dx \cr
& {\text{Use the sum rule for integration}} \cr
& = \int {{e^x}} dx + \int {\frac{1}{x}} dx \cr
& {\text{Apply the formulas: }}\int {{e^x}dx = {e^x} + C,\int {\frac{1}{x}dx = \ln \left| x \right| + C} } \cr
& = {e^x} + \ln \left| x \right| + C \cr} $$