## Elementary Technical Mathematics

$a(x-4)(x-11)$
$ax^2-15ax+44a\longrightarrow$ a is a common factor. $a(x^2-15x+44)$ =$a(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$a(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$ =$a(x-\ \ )(x-\ \ )$ Since the 2nd term is negative and the 3rd is positive, both factors or 44 must be negative =$a(x-4)(x-11)$ -4 and -11 have a sum of -15 and a product of 44.