## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 78

#### Answer

$a(x-4)(x-11)$

#### Work Step by Step

$ax^2-15ax+44a\longrightarrow$ a is a common factor. $a(x^2-15x+44)$ =$a(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$a(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$ =$a(x-\ \ )(x-\ \ )$ Since the 2nd term is negative and the 3rd is positive, both factors or 44 must be negative =$a(x-4)(x-11)$ -4 and -11 have a sum of -15 and a product of 44.

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