Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 34

Answer

$(a+7)(a-2)$

Work Step by Step

$a^2+5a-14$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(a\ \ \ \ \ \ )(a\ \ \ \ \ \ )$ $=(a+\ )(a-\ )$ The factors of -14 must have unlike signs. $=(a+7)(a-2)$ 7 and -2 have a sum of 5 and a product of -14.
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