Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 54

Answer

$(x+8)(x-16)$

Work Step by Step

$x2-8x-128$ has no common monomial factor =$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$ =$(x+\ \ )(x-\ \ )$ The factors of -128 must have unlike signs. =$(x+8)(x-16)$ 8 and -16 have a sum of -8 and a product of -128.
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