## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 44

#### Answer

$(x-3)(x-5)$

#### Work Step by Step

$x^2-8x+15$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$ $=(x-\ )(x-\ )$ Since the 2nd term is negative and the 3rd is positive, both factors of 15 must be negative. $=(x-3)(x-5)$ -3 and -5 have a sum of -8 and a product of 15.

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