Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 77

Answer

$2b(a+6)(a-4)$

Work Step by Step

$2a^2b+4ab-48b$ 2b is a common factor. $2b(a^2+2a-24)$ =$2b(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$2b(a\ \ \ \ \ \ \ )(a\ \ \ \ \ \ \ )$ =$2b(a+\ \ )(a-\ \ )$ The factors of -24 must have unlike signs. =$2b(a+6)(a-4)$ 6 and -4 have a sum of 2 and a product of -24.
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