## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 67

#### Answer

$3x(y-3)^2$

#### Work Step by Step

$3xy^2-18xy+27x\longrightarrow$ 3x is a common factor. $3x(y^2-6y+9)$ =$3x(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$3x(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$ =$3x(y-\ \ )(y-\ \ )$ Since the 2nd term is negative and the 3rd is positive, the factors of 9 must both be negative. =$3x(y-3)(y-3)$ -3 and -3 have a sum of -6 and a product of 9. Since $y-3$ is repeated as a factor it is written as an exponent.

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