## Elementary Technical Mathematics

$(y-4)(y-10)$
$y^2-14y+40$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(y\ \ \ \ \ \ )(y\ \ \ \ \ \ )$ $=(y+\ )(y-\ )$ Since the 2nd term is negative and the 3rd is positive, both factors of 40 must be negative. $=(y-4)(y-10)$ -4 and -10 have a sum of -14 and a product of 40.