Answer
$(y+20)(y-6)$
Work Step by Step
$y2+14y-120$ has no common monomial factor
=$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$
=$(y+\ \ )(y-\ \ )$ The factors of -120 must have unlike signs.
=$(y+20)(y-6)$ 20 and -6 have a sum of 14 and a product of -120.
