Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 36

Answer

$(x+3)(x-7)$

Work Step by Step

$x^2-4x-21$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$ $=(x+\ )(x-\ )$ The factors of -21 must have unlike signs. $=(x+3)(x-7)$ 3 and -7 have a sum of -4 and a product of -21.
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