Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise - Page 350: 43

Answer

$(x+6)(x-15)$

Work Step by Step

$x^2-9x-90$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$ $=(x+\ )(x-\ )$ The factors of -90 must have unlike signs. $=(x+6)(x-15)$ 6 and -15 have a sum of -9 and a product of -90.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.