Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 72

Answer

$(x+24)(x-16)$

Work Step by Step

$x^2+8x-384$ has no common monomial factors. =$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$ =$(x+\ \ )(x-\ \ )$ The factors of -384 must have unlike signs. =$(x+24)(x-16)$ 24 and -16 have a sum of 8 and a product of -384.
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