## Elementary Technical Mathematics

$(y+3)(y+14)$
$y^2+17y+42$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(y\ \ \ \ \ \ )(y\ \ \ \ \ \ )$ $=(y+\ )(y+\ )$ All signs in the trinomial are positive. $=(y+3)(y+14)$ 3 and 14 have a sum of 17 and a product of 42. 6 and 7 have a product of 42, but their sum is only 13. 42 is not divisible by 5 or 4, so the next factor to check is 3.