Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 37

Answer

$(y+3)(y+14)$

Work Step by Step

$y^2+17y+42$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(y\ \ \ \ \ \ )(y\ \ \ \ \ \ )$ $=(y+\ )(y+\ )$ All signs in the trinomial are positive. $=(y+3)(y+14)$ 3 and 14 have a sum of 17 and a product of 42. 6 and 7 have a product of 42, but their sum is only 13. 42 is not divisible by 5 or 4, so the next factor to check is 3.
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