Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 98


$ 3xy(3x+2y)(2x+5y)$

Work Step by Step

$ 18x^{3}y+57x^{2}y^{2}+30xy^{3}\qquad$...factor out the common term, $3xy$. $=3xy(6x^{2}+19xy+10y^{2})$ ... Searching for two factors of $ac=60$ whose sum is $b=19,$ we find$\qquad 4$ and $15.$ Rewrite the middle term and factor in pairs: $=3xy(6x^{2}+4xy+15xy+10y^{2})=$ $=3xy[2x(3x+2y)+5y(3x+2y)]$ =$ 3xy(3x+2y)(2x+5y)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.