Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 122



Work Step by Step

$(y+1)^{3}+1\qquad$...recognize a sum of two cubes:$\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$ $=(y+1)^{3}+1^{3}$ $=(y+1+1)((y+1)^{2}-(y+1)\cdot 1+1^{2})\qquad$...simplify. $=(y+2)(y^{2}+2y+1-y-1+1)$ $=(y+2)(y^{2}+y+1)$
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