Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 101



Work Step by Step

$15a^{2}+11ab-14b^{2}$ ... Searching for two factors of $ac=-210$ whose sum is $b=21,$ we find$\qquad-10$ and $21.$ Rewrite the middle term and factor in pairs: $=15a^{2}-10ab+21ab-14b^{2}=$ $=5a(3a-2b)+7b(3a-2b)]$ =$(3a-2b)(5a+7b)$
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