Answer
$(x+1)(2x+1)(5x-6)$
Work Step by Step
$ 10x^{2}(x+1)-7x(x+1)-6(x+1)\qquad$...factor out the common term, $(x+1)$
$=(x+1)(10x^{2}-7x-6)$
... Searching for two factors of $ac=-60$ whose sum is $b=-7,$
we find$\qquad 5$ and $-12.$
Rewrite the middle term and factor in pairs:
$=(x+1)(10x^{2}+5x-12x-6)=$
$=(x+1)[5x(2x+1)-6(2x+1)]$
=$(x+1)(2x+1)(5x-6)$
