Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 106



Work Step by Step

$ bx^{2}-4b+ax^{2}-4a\qquad$...factor in pairs. $=(bx^{2}-4b)+(ax^{2}-4a)$ $=b(x^{2}-4)+a(x^{2}-4)$ $=(x^{2}-4)(b+a)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(x-2)(x+2)(b+a)$
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