Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 117

Answer

$(x-7-2a)(x-7+2a)$

Work Step by Step

$(x-7)^{2}-4a^{2}\qquad$...rewrite $4a^{2}$ as $(2a)^{2}$ $=(x-7)^{2}-(2a)^{2}\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(x-7-2a)(x-7+2a)$
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