Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 118



Work Step by Step

$(x-6)^{2}-9a^{2}\qquad$...rewrite $9a^{2}$ as $(3a)^{2}$ $=(x-6)^{2}-(3a)^{2}\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(x-6-3a)(x-6+3a)$
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