Answer
$(x-1)(2x+1)(6x-5)$
Work Step by Step
$ 12x^{2}(x-1)-4x(x-1)-5(x-1)\qquad$...factor out the common term, $(x-1)$
$=(x-1)(12x^{2}-4x-5)$
... Searching for two factors of $ac=-60$ whose sum is $b=-4,$
we find$\qquad 6$ and $-10.$
Rewrite the middle term and factor in pairs:
$=(x-1)(12x^{2}+6x-10x-5)=$
$=(x-1)[6x(2x+1)-5(2x+1)]$
=$(x-1)(2x+1)(6x-5)$
