Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 105



Work Step by Step

$ a^{2}y-b^{2}y-a^{2}x+b^{2}x\qquad$...factor in pairs. $=(a^{2}y-b^{2}y)+(-a^{2}x+b^{2}x)$ $=y(a^{2}-b^{2})-x(a^{2}-b^{2})$ $=(a^{2}-b^{2})(y-x)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(a-b)(a+b)(y-x)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.