Answer
$ 2xy(x-y)(5x-2y)$
Work Step by Step
$ 10x^{3}y-14x^{2}y^{2}+4xy^{3}\qquad$... factor out the common term, $2xy$
$=2xy(5x^{2}-7xy+2y^{2})$
... Searching for two factors of $ac=10$ whose sum is $b=-7,$
we find$\qquad-5$ and $-2.$
Rewrite the middle term and factor in pairs:
$=2xy(5x^{2}-5xy-2xy+2y^{2})=$
$=2xy[5x(x-y)-2y(x-y)]$
=$ 2xy(x-y)(5x-2y)$
