Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 102



Work Step by Step

$25a^{2}+25ab+6b^{2}$ ... Searching for two factors of $ac=150$ whose sum is $b=25,$ we find$\qquad 10$ and $15.$ Rewrite the middle term and factor in pairs: $=25a^{2}+10ab+15ab+6b^{2}=$ $=5a(5a+2b)+3b(5a+2b)]$ =$(5a+2b)(5a+3b)$
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