Answer
$25a^{2}+25ab+6b^{2}$
Work Step by Step
$25a^{2}+25ab+6b^{2}$
... Searching for two factors of $ac=150$ whose sum is $b=25,$
we find$\qquad 10$ and $15.$
Rewrite the middle term and factor in pairs:
$=25a^{2}+10ab+15ab+6b^{2}=$
$=5a(5a+2b)+3b(5a+2b)]$
=$(5a+2b)(5a+3b)$
