Answer
$16(4-t)(4+t)$
Work Step by Step
$ 256-16t^{2}\qquad$...factor out the common term, $16$.
$=16(16-t^{2})\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$
$=16(4-t)(4+t)$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 463: 123
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