## Introductory Algebra for College Students (7th Edition)

$5y^2-6y-8$
Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $(5y+4)(y-2) ,$ is \begin{array}{l}\require{cancel} 5y(y)+5y(-2)+4(y)+4(-2) \\\\= 5y^2-10y+4y-8 \\\\= 5y^2-6y-8 .\end{array}