Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 4

Answer

$y^2+y-12$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (y-3)(y+4) ,$ is \begin{array}{l}\require{cancel} y(y)+y(4)-3(y)-3(4) \\\\= y^2+4y-3y-12 \\\\= y^2+y-12 .\end{array}
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