## Introductory Algebra for College Students (7th Edition)

$21x^4-41x^2+10$
Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $(7x^2-2)(3x^2-5) ,$ is \begin{array}{l}\require{cancel} 7x^2(3x^2)+7x^2(-5)-2(3x^2)-2(-5) \\\\= 21x^4-35x^2-6x^2+10 \\\\= 21x^4-41x^2+10 .\end{array}