## Introductory Algebra for College Students (7th Edition)

$28y^2-51y+20$
Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $(4y-5)(7y-4) ,$ is \begin{array}{l}\require{cancel} 4y(7y)+4y(-4)-5(7y)-5(-4) \\\\= 28y^2-16y-35y+20 \\\\= 28y^2-51y+20 .\end{array}