Answer
$y^4-1$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $
(y^2+1)(y^2-1)
,$ is
\begin{array}{l}\require{cancel}
y^2(y^2)-1(1)
\\\\=
y^4-1
.\end{array}