Answer
$4x^2-\dfrac{1}{4}$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $
\left( 2x+\dfrac{1}{2} \right)\left( 2x-\dfrac{1}{2} \right)
,$ is
\begin{array}{l}\require{cancel}
2x(2x)-\dfrac{1}{2}\left( \dfrac{1}{2} \right)
\\\\=
4x^2-\dfrac{1}{4}
.\end{array}