Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 11

Answer

$12y^2-43y+35$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (3y-7)(4y-5) ,$ is \begin{array}{l}\require{cancel} 3y(4y)+3y(-5)-7(4y)-7(-5) \\\\= 12y^2-15y-28y+35 \\\\= 12y^2-43y+35 .\end{array}
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