Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 43

Answer

$x^{20}-25$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $ (x^{10}+5)(x^{10}-5) ,$ is \begin{array}{l}\require{cancel} x^{10}(x^{10})-5(5) \\\\= x^{20}-25 .\end{array}
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