Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 3

Answer

$y^2-4y-21$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (y-7)(y+3) ,$ is \begin{array}{l}\require{cancel} y(y)+y(3)-7(y)-7(3) \\\\= y^2+3y-7y-21 \\\\= y^2-4y-21 .\end{array}
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