## Introductory Algebra for College Students (7th Edition)

$16-9y^2$
Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $(4-3y)(4+3y) ,$ is \begin{array}{l}\require{cancel} 4(4)-3y(3y) \\\\= 16-9y^2 .\end{array}