Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 7

Answer

$4y^2-y-3$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (4y+3)(y-1) ,$ is \begin{array}{l}\require{cancel} 4y(y)+4y(-1)+3(y)+3(-1) \\\\= 4y^2-4y+3y-3 \\\\= 4y^2-y-3 .\end{array}
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