Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 367: 1

Answer

$x^2+10x+24$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (x+4)(x+6) ,$ is \begin{array}{l}\require{cancel} x(x)+x(6)+4(x)+4(6) \\\\= x^2+6x+4x+24 \\\\= x^2+10x+24 .\end{array}
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