Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 72



Work Step by Step

Using the Distributive Property, the given expression, $ (2a-1)(a^2-4a+3) ,$ is equivalent to \begin{array}{l}\require{cancel} 2a(a^2)+2a(-4a)+2a(3)-1(a^2)-1(-4a)-1(3) \\\\= 2a^3-8a^2+6a-a^2+4a-3 \\\\= 2a^3+(-8a^2-a^2)+(6a+4a)-3 \\\\= 2a^3-9a^2+10a-3 .\end{array}
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