Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 60

Answer

$x^2-2x-24$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the Distributive Property, the given expression, $ (x+4)(x-6) ,$ is equivalent to \begin{array}{l}\require{cancel} x(x)+x(-6)+4(x)+4(-6) \\\\= x^2-6x+4x-24 \\\\= x^2-2x-24 .\end{array}
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