Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 18

Answer

$36x^{2}$

Work Step by Step

Using $(x^ay^b)^c=x^{ac}y^{bc}$ or the products-to-powers rule, the given expression, $ (-6x)^2 ,$ simplifies to \begin{array}{l}\require{cancel} (-6)^{1(2)}x^{1(2)} \\\\= (-6)^{2}x^{2} \\\\= 36x^{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.