Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 64

Answer

$3x^2+11x-20$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the Distributive Property, the given expression, $ (3x-4)(x+5) ,$ is equivalent to \begin{array}{l}\require{cancel} 3x(x)+3x(5)-4(x)-4(5) \\\\= 3x^2+15x-4x-20 \\\\= 3x^2+11x-20 .\end{array}
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