Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 70



Work Step by Step

Using the Distributive Property, the given expression, $ (y-2)(y^2-4y+3) ,$ is equivalent to \begin{array}{l}\require{cancel} y(y^2)+y(-4y)+y(3)-2(y^2)-2(-4y)-2(3) \\\\= y^3-4y^2+3y-2y^2+8y-6 \\\\= y^3+(-4y^2-2y^2)+(3y+8y)-6 \\\\= y^3-6y^2+11y-6 .\end{array}
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