Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 22

Answer

$16y^{20}$

Work Step by Step

Using $(x^ay^b)^c=x^{ac}y^{bc}$ or the products-to-powers rule, the given expression, $ (-2y^5)^4 ,$ simplifies to \begin{array}{l}\require{cancel} (-2)^{1(4)}y^{5(4)} \\\\= (-2)^{4}y^{20} \\\\= 16y^{20} .\end{array}
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