Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 65



Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the Distributive Property, the given expression, $ \left( \dfrac{1}{4}x+4 \right)\left( \dfrac{3}{4}x-1 \right) ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{1}{4}x\left( \dfrac{3}{4}x \right)+\dfrac{1}{4}x(-1)+4\left( \dfrac{3}{4}x \right)+4(-1) \\\\= \dfrac{3}{16}x^2-\dfrac{1}{4}x+\dfrac{12}{4}x-4 \\\\= \dfrac{3}{16}x^2+\dfrac{11}{4}x-4 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.