Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 359: 71



Work Step by Step

Using the Distributive Property, the given expression, $ (2a-3)(a^2-3a+5) ,$ is equivalent to \begin{array}{l}\require{cancel} 2a(a^2)+2a(-3a)+2a(5)-3(a^2)-3(-3a)-3(5) \\\\= 2a^3-6a^2+10a-3a^2+9a-15 \\\\= 2a^3+(-6a^2-3a^2)+(10a+9a)-15 \\\\= 2a^3-9a^2+19a-15 .\end{array}
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