Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 4

Answer

$y^{20}$

Work Step by Step

Using $x^a \cdot x^b=x^{a+b}$ or the product rule, the given expression, $ y\cdot y^{19} ,$ simplifies to \begin{array}{l}\require{cancel} y^{1+19} \\\\= y^{20} .\end{array}
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