Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 62

Answer

$x^2-4x-96$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the Distributive Property, the given expression, $ (x-12)(x+8) ,$ is equivalent to \begin{array}{l}\require{cancel} x(x)+x(8)-12(x)-12(8) \\\\= x^2+8x-12x-96 \\\\= x^2-4x-96 .\end{array}
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