Answer
$-32x^{35}$
Work Step by Step
Using $(x^ay^b)^c=x^{ac}y^{bc}$ or the products-to-powers rule, the given expression, $
(-2x^7)^5
,$ simplifies to
\begin{array}{l}\require{cancel}
(-2)^{1(5)}x^{7(5)}
\\\\=
(-2)^{5}x^{35}
\\\\=
-32x^{35}
.\end{array}