Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 83



Work Step by Step

Simplify. $ (\sqrt{x-4}+\sqrt {x+1})=5$ Take square on both sides. we have, $ (\sqrt{x-4}+\sqrt {x+1})^2=5^2$ or, $(x-4)^2+(x+1)^2+2 (\sqrt{x-4}+\sqrt {x+1})=25$ or, $2x-28=-2 (\sqrt{x-4}+\sqrt {x+1})$ Thus, $x^2-28x+196=x^2-3x-4$ $-25x=-200$ Hence, we can conclude that $x=8$.
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